Question

dada a funçao quadratica definida por f(x)= x2+5+6 determine:
a) f(4) b) f(0) c) f(-1/5) d) f(-1)

Answer 1

f(x) = x² + 5 + 6

a)

f(4) = 4² + 5 + 6
f(4) = 27
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b)

f(0) = 0² + 5 + 6
f(0) = 11

c)

f(-1/5) = (-1/5)² + 5 + 6
f(-1/5) = 1/25 + 5 + 6
f(-1/5) = 1/25 + 125/25 + 150/25
f(-1/5) = 276/25

d)

f(-1) = (-1)² + 5 + 6
f(-1) = 12


Forte abraço!