Question

Dada a função h(x)= x ao quadrado sobre x+2, calcule f(0)+ f(4)- f(-1) =

Answer 1

Vou supor que $h(x) = f(x)$

$f(x)= \frac{x^2}{x+2} \\ f(0)= \frac{0^2}{0+2}=0/2=0\\ f(4)= \frac{4^2}{4+2}=16/6=8/3\\ f(-1)= \frac{-1^2}{-1+2}=1/1=1\\ f(0)+f(4)-f(-1)=\\ 0+(8/3)-1 = (8-3)/3=5/3$

Answer 2

H(x) = x²/x+2
H(0) = 0/2 = 0
H(4) = 4²/6 = 16/6 = 8/3
H(-1)= (-1)²/1 = 1/1 = 1

H(0) + H(4) -H(-1) = 0+(8/3)-1 = 5/3