Question

Dada a função
g(x)=3x^-2x-5 calcule:

a) g (3)
b) g (-2)
c) g (0) + g (4)

Answer 1

$g(x) = 3x {}^{2} - 2x - 5 \\ \\ g(3) = 3(3) {}^{2} - 2 \times 3 - 5 \\ g(3) = 27 - 6 - 5 \\ g(3) = 16 \\ \\ g( - 2) = 3( - 2) {}^{2} - 2( - 2) - 5 \\ g( - 2) = 3 \times 4 + 4 - 5 \\ g( - 2) = 12 + 4 - 5 \\ g( - 2) = 11 \\ \\ g(0) = 3 \times 0 {}^{2} - 2 \times 0 - 5 \\ g(0) = 0 - 0 - 5 \\ g(0) = - 5 \\ \\ g(4) = 3(4) {}^{2} - 2 \times 4 - 5 \\ g(4) = 3 \times 16 - 8 - 5 \\ g(4) = 48 - 13 \\ g(4) = 35 \\ \\ g(0) - g(4) = - 5 - 35 = - 40$