Question

Dada a função f(x) = x² + x, com x ∈ R e f(x) ∈ R, o valor de f(1) + 3. f(-1) - 5. f(0) é: *

a) - 12
b) - 24
c) 12
d) 24

Answer 1

$\mathsf{f(x)=x^2+x}\\\mathsf{f(1)=1^2+1=1+1=2}\\\mathsf{{(-1)}^2+(-1)=1-1=0}\\\mathsf{f(0)=0^2+0=0}$

$\mathsf{f(1)+3f(-1)-5f(0)=2+3.0-5.0=2}$

reveja o gabarito.