Question

dada a funçao f(x)=x2-x calcule: f(1)+3f(-1)-5f(3)+f(0)

Answer 1

f(1)= 1²- 1= 1 - 1= 0

f(-1)=(-1)²- (-1)= 1 + 1=2

f(3)= 3²- 3= 9 -3= 6

f(0)= 0²-0= 0

substituir em:
f(1)+3f(-1)-5f(3)+f(0)=

0 + 3. 2 - 5.6 +0=

6 - 30= -24