Question

Dada a função f (x) =x2-x calcule f (1)+3 f (-2)-5. f (3) f (-1)?

Answer 1

f(1)= 1²-1=0
f(-2)=(-2)² - (-2) = 4+2=6 
f(3) = 3² -3 = 9-3 = 6
f(-1) = (-1)² - (-1) = 1+1=2

f(1) + 3f(-2)-5 . f(3) . f(-1)
0 + (3.6 -5).(6).(2) 
0+13.12 = 156