Matemática, perguntado por duda20022002222, 11 meses atrás

Dada a função f(x)=x²-6x+8, determine x, se houver, para que se tenha :
a) f(x)=3

Soluções para a tarefa

Respondido por GeBEfte
5

f(x)~=~x^2-6x+8\\\\\\\\Para~f(x)~=~3:\\\\\\3~=~x^2-6x+8\\\\\\\boxed{x^2-6x+5~=~0}\\\\\\\\\Delta~=~(-6)^2-4.1.5\\\\\\\Delta~=~36-20\\\\\\\boxed{\Delta~=~16}\\\\\\\\x'~=~\frac{6+\sqrt{16}}{2~.~1}\\\\\\x'~=~\frac{6+4}{2}\\\\\\\boxed{x'~=~5}\\\\\\\\x''~=~\frac{6-\sqrt{16}}{2~.~2}\\\\\\x''~=~\frac{6-4}{2}\\\\\\\boxed{x''~=~1}


duda20022002222: Muito obrigado !
GeBEfte: Tranquilo
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