Question

Dada a função f (x)=x2-5×+4, Determine a) f (2)b) f (-1)c) f (0)

Answer 1

f(2) = 2² -5(2) + 4= 4 - 10 + 4 = -2
f(-1) = (-1)² -5 (-1) + 4 = 1 + 5 + 4 = 10
f(0) = 0² - 5(0) + 4 = 4

Answer 2

Olá!!!

Resolução!!!

a)
f ( x ) = x² - 5x + 4
f ( 2 ) = ( 2 )² - 5 • ( 2 ) + 4
f ( 2 ) = 4 - 10 + 4
f ( 2 ) = 4 - 6
f ( 2 ) = - 2

b)
f ( x ) = x² - 5x + 4
f ( - 1 ) = ( - 1 )² - 5 • ( - 1 ) + 4
f ( - 1 ) = 1 - ( - 5 ) + 4
f ( - 1 ) = 1 + 5 + 4
f ( - 1 ) = 6 + 4
f ( - 1 ) = 10

c)
f ( x ) = x² - 5x + 4
f ( 0 ) = ( 0 )² - 5 • ( 0 ) + 4
f ( 0 ) = 0 - 0 + 4
f ( 0 ) = 0 + 4
f ( 0 ) = 4

Espero ter ajudado!!!