Question

dada a função f:(x)=x²-3x+2, calcule: f(0), f(1), (-1), f(2)

Answer 1

f(0) -> f:(x)=x²-3x+2
f(0) -> f:(0)=0²-3*0+2 = 2
f(1) -> f:(1)=1²-3*1+2 = 0
f(-1) -> f:(-1)=(-1²)-3*(-1)+2 = 5
f(2) -> f:(2)=2²-3*2+2 = 0

Answer 2

Dada a função f:(x)=x²-3x+2, calcule: f(0), f(1), (-1), f(2)
F(0) = (0)^2 - 3(0) + 2 ==> 0-0+2==>  2
F(1) = (1)^2 - 3(1) + 2 ==> 1-3+2==> 0
F(-1) = (-1)^2 - 3(-1) + 2 ==> 1+3+2==>  6
F(2) = (2)^2 - 3(2) + 2 ==> 4-6+2==>  0