Question

Dada a função f(x) = x²+3x+1 Calcule f(a+1)

Answer 1

Resposta:

$f(x) = {x}^{2} + 3x + 1 \\ f(a + 1) = {(a + 1)}^{2} + 3(a + 1) + 1 \\ f(a + 1) = (a + 1)(a + 1) + 3a + 3 + 1 \\ f(a + 1) = {a}^{2} + a + a + 1 + 3a + 1 \\ f(a + 1) = {a}^{2} + 2a + 1 + 3a + 1 \\ f(a +1) = {a}^{2} + 2a + 3a + 1 + 1 \\ f(a + 1) = {a}^{2} + 5a + 2$

Bons estudos!

Answer 2

f(a+1)=(a+1)²+3(a+1)+1

f(a+1)=a²+2a+1+3a+3+1

f(a+1)=a²+5a+2

Espero ter ajudado

bons estudos :)