dada a funçao f(x)=x ao quadrado -x calcule f(1)+3 f(-1)-5 f(3)+ f(0)
Soluções para a tarefa
Respondido por
2
a)
f(x) = x² - x
f(1) = 1² - 1 = 1 - 1 = 0
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
Resp.:
f (1) + 3 = 0 + 3 = 3
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
b)
R.:
f(-1) - 5 = 0 - 5 = - 5
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
f(x) = x² - x
f(-1) = (-1)² - 1 = 1 - 1 = 0
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
c)
R.:
f(3) + f(0) = 6 + 0 = 6
****************************
f(x) = x² - x
f(3) = 3² - 3
f(3) = 9 - 3
f(3) = 6
f(x) = x² - x
f(0) = 0² - 0
f(0) = 0
f(x) = x² - x
f(1) = 1² - 1 = 1 - 1 = 0
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
Resp.:
f (1) + 3 = 0 + 3 = 3
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
b)
R.:
f(-1) - 5 = 0 - 5 = - 5
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
f(x) = x² - x
f(-1) = (-1)² - 1 = 1 - 1 = 0
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
c)
R.:
f(3) + f(0) = 6 + 0 = 6
****************************
f(x) = x² - x
f(3) = 3² - 3
f(3) = 9 - 3
f(3) = 6
f(x) = x² - x
f(0) = 0² - 0
f(0) = 0
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