Question

Dada a função f(x)=-x^2+2x-5, determine:

f(-1)=

f(0)=

f(3)=

f(1/2)=

f(0,1)=

Me ajudem por favor!

Answer 1

Resposta:

f(0)=0^2+2.0-5=-5

f(3)=3^2+2.3-5=10

f(1/2)=1/2^2+2.(1/2)-5=1/4+1=5/4

f(0,1)=1/10^2+2(1/10)-5=-4,79