Question

Dada a função f(x)=x^2-2x+1, ache o vértice

Answer 1

Resposta:

f(x)=x^2-2x+1

vx=-b/2a=-2(-2)/2*1 =1

f(1)=1²-2*1+1 =0  é o vy

vértice=(1,0)