Question

Dada a função f(x)= (m-5) x2+3x-1 calcule m

Answer 1

f(x)=(m-5)
x^2+3x-1=0
a=1...b=3...c=-1

primeiro calculamos a formula DELTA
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delta = b^2 - 4 a c
delta = (3)^2 - 4(1)(-1)
delta = 9 - 4(-1)
delta = 9 + 4
delta = 13

segundo calculamos a formula BASKARA
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X = - b +,- \/delta / 2a
X = - (3) +,- \/13 / 2(1)
X = - 3 +,- 3,60/2
X1 = -3+3,60/2》X1 = 0,60/2》X1 = 0,3
X2 = -3-3,60/2》X2 = -6,60/2》
X2 =- 3,30

f(x) = ( m - 5 )
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X1 = m1 = 0,3. :
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f(x) = ( m1 - 5 )
f(x) = ( 0,3 - 5)
f(x) = (-4,7)
f(x) = - 4,7

X2 = m2 = - 3,30 :
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f(x) = ( m2 - 5 )
f(x) = ( - 3,30 - 5 )
f(x) = ( - 8,30)
f(x) = - 8,30