Question

dada a função f(x)=ax+b e sabendo se que f(3)=5 e f(-2)= -5 calcule f(1/2)

Answer 1

3a+b=5
-2a+b=-5 (-1)

3a+b=5------------>3.2+b=5
2a-b=5                  6+b=5
(soma)5a=10        b=1
             a=2

f(x)=ax+b
f(1/2)=2x+1
f(1/2)=2.1/2+1
f(1/2)=1+1
f(1/2)=2