Question

Dada a função f(x)= ax + b e sabendo-se que f(3)= 5 e f(-2)= -5 calcule f(1/2)

Answer 1

f(x) = ax + b

f(3) = 5
f(-2) = -5

3a + b = 5
-2a + b = -5  *(-1)

3a + b = 5
2a - b = 5

5a = 10
a = 10/5
a = 2

3a + b = 5
3*2 + b = 5
6 + b = 5
b = 5 - 6
b = -1

f(x) = 2x - 1

f(1/2) = 2*(1/2) - 1
f(1/2) = 2/2 - 1
f(1/2) = 1 - 1
f(1/2) = 0