Question

Dada a função f (x)=ax+b e sabendo-se que f (3)=5 3 f (-2)=-5 calcule f (1/2)

Answer 1

f(3)=53 ⇒3a+b=53
f(-2) = -5 ⇒-2a+b=-5 ⇒2a-b=5
(3a+b)+(2a-b)=53+5 ⇒5a =58 ⇒a = 58/5
3a+b=53 ⇒ b = 53 - 3a ⇒ b = 53 - 3·(58/5)= 53 - (174/5)=91/5
f(x) = (58/5)x + (91/5)
f(1/2) = (58/5)·(1/2 ) + 91/5 = (58/10 ) + ( 182 /10) = 240/10 = 24