Matemática, perguntado por rfelipemoreira, 1 ano atrás

Dada a função f(x)=5x+3/x-1, calcule f(2/3)

Soluções para a tarefa

Respondido por ScreenBlack
1
f_{(x)}=5x+\dfrac{3}{x}-1\\\\\\
f_{(\frac{2}{3})}=5\left(\dfrac{2}{3}\right)+\dfrac{\dfrac{3}{1}}{\dfrac{2}{3}}-1\\\\\\
f_{(\frac{2}{3})}=\dfrac{10}{3}+\dfrac{9}{2}-1\\\\\\
f_{(\frac{2}{3})}=\dfrac{20+27-6}{6}\\\\
\boxed{f_{(\frac{2}{3})}=\dfrac{41}{6}}

Bons estudos!
Respondido por Menelaus
2
  • Substitua x por 2/3 e resolva.

f(x) = 5x + 3/x - 1

f(2/3) = 5 . 2/3 + 3/(2/3) - 1

f(2/3) = 10/3 + 3 . 3/2 - 1

f(2/3) = 10/3 + 9/2 - 1

f(2/3) = (20 + 27 - 6)/6

f(2/3) = (47 - 6)/6

f(2/3) = 41/6

Resposta: 41/6

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