Question

Dada a função f(x) = 5x + 1, com x∈ R e y∈ R. Determine:
a) f(−2)
b) f(3)
c) f(1)
d) f(0)

Answer 1

Resposta:

voce quer a resposta

Explicação passo-a-passo:

Answer 2

Resposta:

Solução:

a)

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(x) = 5x + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(-\;2) = 5\cdot (-2) + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(-\;2) = -\:10 + 1 \end{array}\right$

$\boxed{ \boxed { \boldsymbol{ \large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(-\;2) = -\:9 \end{array}\right }}} \quad \gets \mathbf{ Resposta }$

b)

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(x) = 5x + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(3) = 5 \cdot 3 + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(3) = 15 + 1 \end{array}\right$

$\boxed{ \boxed { \boldsymbol{ \large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(3) = 16 \end{array}\right }}} \quad \gets \mathbf{ Resposta }$

c)

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(x) = 5x + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(1) = 5 \cdot 1 + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(1) = 5 + 1 \end{array}\right$

$\boxed{ \boxed { \boldsymbol{ \large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(1) = 6 \end{array}\right }}} \quad \gets \mathbf{ Resposta }$

d)

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(x) = 5x + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(0) = 5 \cdot 0 + 1 \end{array}\right$

$\large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(0 ) = 0 + 1 \end{array}\right$

$\boxed{ \boxed { \boldsymbol{ \large \sf \displaystyle \left\begin{array}{l l l l l } \sf f(0 ) = 1 \end{array}\right }}} \quad \gets \mathbf{ Resposta }$

Explicação passo-a-passo:

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