Question

Dada a função f(x)=4x²-2x+1, determine: f(-2), f(-1), f(0), f(1) e f(2)

Answer 1

Explicação passo-a-passo:

f(x)= 4x² - 2x +1

f(-2)= 4.(-2)² -2.(-2) +1

f(-2)= 4.4 + 4 +1

f(-2)= 16 +4+1

f(-2)= 21

f(-1)= 4.(-1)² - 2.(-1) +1

f(-1)= 4.1 +2 +1

f(-1)= 4+2+1

f(-1)= 7

f(0)= 4.0² - 2.0 +1

f(0)= 0 - 0 +1

f(0)= 1

f(1)= 4.1² - 2.1 +1

f(1)= 4 -2 +1

f(1)= 2+1

f(1)= 3

f(2)= 4.2² -2.2 +1

f(2)= 4.4-4 +1

f(2)= 16 -4 +1

f(2)= 12+1

f(2)= 13