Question

Dada a função f(x)=3x³-5x²,Qual o valo de f(2)-f(1)

Answer 1

Resposta:

f(2)=3.2^5-5.2^2

f(2)=3.8-5.4

f(2)=24-20

f(2)=4

f(1)=3.1^3-5.1^2

f(1)=3.1-5.1

f(1)=3-5

f(1)=-2

f(2)-f(1)=4-(-2)=4+2=6

Answer 2

f(2) = 3*$2^{3}$ - 5*$2^{2}$

f(2) = 24 - 20

f(2) = 4

f(1) = 3*$1^{3}$ - 5*$1^{2}$

f(1) = 3 - 5

f(1) = -2

4 - (-2)

4 + 2

6