Question

Dada a função F(x)=3x²-5x, determine o valor de f(4)+ 2 f(0) -f(-3) f(0)+5.f(-1)+f(4) f(-3) -2.f(-1) + f(1)

Answer 1

F(x)=3x²-5x, determine o valor de

f(4)+ 2f(0) - f(-3) = 28 +2.(0) - 42 ==> 28 + 0 - 42 ==> 14

f(4)= 3(4)² - 5(4) = 3.(16) - 20 ==> 48 - 20 = 28

f(0)= 3(0)² - 5(0) = 3.(0) - 0 ==> 0 - 0 = 0

f(-3)= 3(-3)² - 5(-3) = 3.(9) + 15 ==> 27 + 15  = 42
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B) f(0)+5.f(-1)+f(4) = 0 + 8 + 28  ==> 36

f(0) = 3(0)² - 5(0) = 3.(0) - 0 ==> 0 - 0 = 0

f(-1)= 3(-1)² - 5(-1) = 3.(1) + 5 ==> 3 + 5  = 8

f(4)= 3(4)² - 5(4) = 3.(16) - 20 ==> 48 - 20 = 28
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f(-3) - 2.f(-1) + f(1) = 42 -2.(8) + (-2) ==> 42 - 16 - 2 ==> 24

f(-3)= 3(-3)² - 5(-3) = 3.(9) + 15 ==> 27 + 15  = 42

f(-1)= 3(-1)² - 5(-1) = 3.(1) + 5 ==> 3 + 5  = 8

f(1)= 3(1)² - 5(1) = 3.(1) - 5 ==> 3 - 5  = - 2