Question

dada a função F(x)=3x²-5. Determine o valor de: F (3) F(-2) e F(0)

Answer 1

f(x)=3x²-5


f(3)=3*3²-5
f(3)=3*9-5
f(3)=27-5
f(3)=22


f(-2)=3*(-2)²-5
f(-2)=3*4-5
f(-2)=12-5
f(-2)=7

f(0)=0-5
f(0)=-5