Question

Dada a função : f(x) = 3x² + 5, calcule: f(0), f(1), f(2), f(3), f(4) e f(-2) se puder me ajudar agradeço

Answer 1

f(0) = 3x² +5

f(0) = 3·0² +5

f(0) = 0 + 5

f(0) = 5

f(1) = 3·1² + 5

f(1) = 3·1 + 5

f(1) = 3 + 5

f(1) = 8

f(2) = 3·2² + 5

f(2) = 3·4 + 5

f(2) = 12 + 5

f(2) = 17

f(3) = 3·3² + 5

f(3) = 3·9 + 5

f(3) = 27 + 5

f(3) = 32

f(4) = 3·4² + 5

f(4) = 3·16 + 5

f(4) = 48 + 5

f(4) = 53

f(-2) = 3·(-2)² + 5

f(-2) = 3·4 + 5

f(-2) = 12 + 5

f(-2) = 17