Question

Dada a função f(x)=3x2-4x+1, determine:
A)f(1)
B)f(2)
C)f(0)
D)f(/2)
E)(-2)

Answer 1

a)3(1)²-4(1)+1=
3×1-4+1
3-4+1=
0

b)3(2)²-4(1)+1
3×4-4+1
12-4+1
9
C)3(0)²-4(0)+1=
3×0+1=
+1

d)3( √ 2)²-4(√2)+1=
3×2-4√2+1=
6+1-4√2=
7-4√2


e)3(-2)²-4(-2)+1=
3×4+8+1=
12+8+1=
21