Question

dada a funçao f(x)= -2x²+4x-9 , as coordenadas do vertice do grafico da parabola definida por f(x), é:
a- (-7,1) b- (1,-7) c-(0,1) d-(-7,0) e-(0,0)

Answer 1

Ola Valeska

vértices

Vx = -b/2a = -4/-4 = 1

delta
d² = 16 - 72 = -56

Vy = -d²/4a = 56/-8 = -7

B) V(1,-7)