Question

Dada a funcao f(x) = 2x²+3x+2 encontre f(-2) , f(0) , f(5) , f(7)

Answer 1

f(-2) = 2.(-2)²+3.(-2) + 2 = 2.4 - 6 + 2 = 8 - 6 + 2 = 2 + 2 = 4
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f(0)= 2.0² + 3.0 + 2 = 0 + 0 + 2 = 2
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f(5) = 2.5² + 3.5 + 2 = 2.25 + 15 + 2 = 50+15+2= 67
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f(7) = 2.7² + 3.7 + 2 = 2.49 +21 + 2 = 98 + 21 +2 = 119 + 2 = 121

Answer 2

f(x) =  2x²+3x+2
f(-2) = 2.(-2)²+3.(-2)+2 = 2. 4 + (-6)+2 = 8 - 6 +2= 4
f(0) =  2.(0)²+3.(0)+2 = 0 + 0 +2 = 2
f(5) =  2.(5)²+3.(5)+2 = 2. 25 + 15+2 = 50 + 17 = 67
f(7) =  2.(7)²+3.(7)+2 = 2. 49 + 21+2 = 98 + 23 =121