Question

Dada a função f(x)= 2x-6, calcule
f(-3)
f(-1)
f(0)
f(3)
f(1/3)

Answer 1

f(-3)=2.(-3)-6
f(-3)=-6-6
f(-3)=-12

f(-1)=2.(-1)-6
f(-1)=-2-6
f(-1)=-8

f(0)=2.0-6
f(0)=-6

f(3)=2.3-6
f(3)=6-6
f(3)=0

f($\frac{1}{3}$)=2.$\frac{1}{3}$-6
f($\frac{1}{3}$)=$\frac{2}{3}$-6
f($\frac{1}{3}$)=$\frac{2-18}{3}$=$\frac{16}{3}$

Answer 2

f(x)= 2x-6

f(-3)= 2.(-3)-6
f(-3)= -12

f(-1)= 2.(-1)-6
f(-1)= -8

f(0)= 2.0-6
f(0)= -6

f(3)= 2.3-6
f(3)= 0

f(1/3)= 2.1/3-6
f(1/3)= 2/3-6
f(1/3)= -4/3