Question

Dada a função f(x)=2x+1 caucule.

A)f(0)
B)f(1)
C)f(-1)
d)f(3)
e)f(-5)
f)f(5)

Answer 1

a- f(0)=2x+1
f(0)=2*0+1
F(0)+1

b- f(1)=2x+1
f(1)=2*1+1
f(1)=3

c- f(-1)=2*(-1)+1
f(-1)= -1

d- f(3)=2*3+1
f(3)=7

e- f(-5)=2*(-5)+1
f(-5)= -9
f_ f(5)=2*5+1
f(5)=11