Question

Dada a função: f:R ->R definida por f (x)=x2-2x+1 calcule:
a) f (0)
b)f (2)
c)f (-3)

Answer 1

$f(x) = {x}^{2} - 2x + 1 \\ a)f(0) = {0}^{2} - 2 \times 0 + 1 \\ f(0) = 1 \\ \\ b)f(2) = {2}^{2} - 2 \times 2 + 1 \\ f(2) = 4 - 4 + 1 \\ f(2) = 1 \\ \\ c)f( - 3) = ( { - 3)}^{2} - 2 \times ( - 3) + 1 \\ f( - 3) = 9 + 6 + 1 \\ f( - 3) = 16$

Answer 2

Olá!

$a) \: f(0) = {0}^{2} - 2 \times 0 + 1 \\ f(0) = 0 - 0 + 1 \\ \boxed{f(0) = 1}$

$b) \: f(2) = {2}^{2} - 2 \times 2 + 1 \\ f(2) = 4 - 4 + 1 \\ \boxed{f(2) = 1}$

$c) \: f( - 3) = {( - 3)}^{2} - 2 \times ( - 3) + 1 \\ f( - 3) = 9 + 6 + 1 \\ \boxed{f( - 3) = 16}$

Espero ter ajudado! :)