Question

dada a função f: R -> R definida por f(x)=
$x2$
-5x+6, calcule:

a) f(2), f(-3) e f(0) ​

Answer 1

f(x)=x²-5x+6

f(2)=2²-5.2+6=4-10+6=0

f(-3)=(-3)²-5.(-3)+6=9+15+6=30

f(0)=0²-5.0+6=6