Question

Dada a função f:IR-> iR definida por f(x)= 3x^2- 5X+1 . Calcule

a) F(3)
b) f ( 1/3) FRAÇÃO
c) f ( 0 )
d) f (-4)

Answer 1

f(3)3(3)^2-5(3)+1=>
f(3) 3(9)-15+1=>
f(3) 13

f(1/3) 3(1/3)^2-5(1/3)+1=>
f(1/3) 3/9-5/3+1=>
f(1/3) -12/9+1=>
f(1/3) 3/9=>1/3

f(0) 3(0)^2-5(0)+1=>
f(0) 1

f(-4) 3(-4)^2-5(-4)+1=>
f(-4) 3(16)+20+1
f(-4) 69

espero ter ajudado