Question

Dada a função exponencial f (x)=4^x,determine f( -1/3)​

Answer 1

Resposta:

Explicação passo-a-passo:

$f(x) = 4^{x}\\ f(-\frac{1}{3})= 4^{-\frac{1}{3} }$

$4^{-\frac{1}{3} } = \frac{1}{4^{\frac{1}{3} } } = \frac{1}{\sqrt[3]{4} } = \frac{1}{\sqrt[3]{2^{2} } }$

$\frac{1}{\sqrt[3]{2^{2} } } . \frac{\sqrt[3]{2} }{\sqrt[3]{2} } = \frac{\sqrt[3]{2} }{\sqrt[3]{2^{3} } } = \frac{\sqrt[3]{2} }{2}$

$f(-\frac{1}{3}) = \frac{\sqrt[3]{2} }{2}$