Question

dada a função definida por:f(x)=x ao quadrado-6x+9,calcule:
a) f(0)
b)f(1)
c)f(-2)
d)f(3)

Answer 1

f(x)=x^2-6x+9

f(0)=0^2-6.0+9=0-0+9=+9

f(1)=1^2-6.1+9=1-6+9=4

f(-2)=(-2)^2-6.(-2)+9=4+12+9=25

f(3)=3^2-6.3+9=9-18+9=0