Question

dada a funcao de f:ℝ----ℝ definida por f(x)=x-x², cacule a)f(2) b)f(-1) c)f(1) d)f(-3) e)f(1/2) f) f(1/3)

Answer 1

f(x)= x - x²

a) f (2)= 2 - 2²
    f (2)= 2 - 4
    f (2)= -2

b) f (-1)= -1 - (-1)²
    f (-1)= -1 - 1
    f (-1)= -2

c) f (1)= 1 - 1²
    f (1)= 1 - 1
    f (1)= 0

d) f (-3)= -3 - (-3)²
    f (-3)= -3 -9
    f (-3)= -12

e) f (1/2)= 1/2 - (1/2)²
    f (1/2)= 1/2 - 1/4
    f (1/2)= 1/4

f) f (1/3)= 1/3 - (1/3)²
   f (1/3)= 1/3 - 1/9
   f (1/3)= 2/9