dada a funcao afim f(x)=-2x+3 determine f(f(1/3))
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Respondido por
18
f(x) = -2x + 3
f(1/3) = -2 . (1/3) + 3
f(1/3) = -2/3 + 3
f(1/3) = (-2 + 9) / 3
f(1/3) = 7/3
f(7/3) = -2 . (7/3) + 3
f(7/3) = -14/3 + 3
f(7/3) = (-14 + 9) / 3
f(7/3) = -5/3
f(1/3) = -2 . (1/3) + 3
f(1/3) = -2/3 + 3
f(1/3) = (-2 + 9) / 3
f(1/3) = 7/3
f(7/3) = -2 . (7/3) + 3
f(7/3) = -14/3 + 3
f(7/3) = (-14 + 9) / 3
f(7/3) = -5/3
Respondido por
0
f(x) = - 2x + 3
• f(1/3) = - 2 . 1/3 + 3
f(1/3) = - 2/3 + 3
f(1/3) = (- 2 + 9)/3
f(1/3) = 7/3
• f(7/3) = - 2 . 7/3 + 3
f(7/3) = - 14/3 + 3
f(7/3) = (- 14 + 9)/3
f(7/3) = - 5/3
att. yrz
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