Question

dada a função afim f (x)= 2x+ 3,determine

a) f (1)=

b) f (0)=

c) f (1/3)=

d) f (-1/2)=

Answer 1

Dada a função afim f(x)= 2x+3, determine:

a) f(1)=
x=1
f(x) = 2x + 3
f(1) = 2(1) + 3
f(1) = 2 + 3
f(1) = 5


b) f(0)
x=0
f(x) = - 2x + 3
f(0) = 2(0) + 3
f(0) = 0 + 3
f(0) = 3


c) f(1/3)
x = 1/3
f(x) = 2x + 3
f(1/3) = 2(1/3) + 3
f(1/3) = 2(1)/3 + 3
f(1/3) = 2/3 + 3

f(1/3) = 2/3 + 3/1 Obs: 3 é o mmc
1.(2) + 3(3)
f(1/3) = -------------------
3

2 + 9
f(1/3) = -------------
3

f(1/3) = 11/3



d) f(-1/2)
x = - 1/2
f(x) = 2x + 3
f(-1/2) = 2(-1/2) + 3
f(-1/2) = 2(-1)/2 + 3
f(-1/2) = -2/2 + 3
f(-1/2) = -1 + 3
f(-1/2) = 2

Answer 2

f(x) = 2x + 3

a)
f(1) = 2.1 + 3
f(1) = 2 + 3 = 5

b)
f(0) = 2.0 + 3
f(0) = 0 + 3 = 3

c)
f(1/3) = 2.1/3 + 3
f(1/3) = 2/3 + 3
f(1/3) = 2/3 + 3.3/3
f(1/3) = 2/3 + 9/3 = 11/3

d)
f(-1/2) = 2.(-1/2) + 3
f(-1/2) = -1 + 3 = 2