Question

dada a função afim f (x)=- 2x +3, determine :

Answer 1

f(x)=-2x+3

a) f(1) = -2.1+3 = 1

b) f(0) = -2.0+3 = 3

c) f(1/3) = $-2. \frac{1}{3} +3 = \frac{-2}{3} +3 = \frac{-2+(3.3)}{3} = \frac{-2+9}{3} = \frac{7}{3}$

d)$f( \frac{-1}{2} )=-2. \frac{-1}{2} +3= \frac{2}{2} +3=1+3=4$