Question

dada a f(x)=(e^x)*cos (x) calcule f(0) 3f'(0) 5f''(0)

Answer 1

sendo:

f(x) = (e^x) * cos(x)

f'(x) = -(e^x) * sen(x)

f"(x) = -(e^x) * cos(x)

f(0) = 1

3f'(0) = 0

5f"(0) = -5