Question

Dada a expressão y= (sen 0°-sen 3π/2+sen π/2) / (2.sen π/6) a sua solução é:


a) 0


b) 1


c) 2


d) 3


e) 4

Answer 1

Vamos là.

y = ( sen(0) - sen(3π/2) + sen(π/2) ) / ( 2sen(π/6) )

y = ( 0 + 1 + 1 )/(2/2)

y = 2/1 = 2 (C)

Answer 2

Resposta:

Letra C

Explicação passo a passo:

$\pi~equivale~a~180\°\\\\\ sen0\°=0\\\\sen \frac{3\pi }{2}= sen270\° = -1 \\\\sen\frac{\pi }{2}=sen90\°=1\\\\sen\frac{\pi }{6}=sen30\°= \frac{1}{2}$

$(sen0\°-sen\frac{3\p\pi }{2} +sen\frac{\pi }{2}) :2sen\frac{\pi }{6}=[0-(-1)+1]:2:\frac{1}{2} =(0+1+1):1=2.1=2$