Question

dada a expressão
x= -b+✓b²-4.a.c
__________
2.a,

sendo a=1,, b= .7 e C= 10, qual o valor numérico de x?​

Answer 1

Determinar valor numérico de x

$\sf x = \dfrac{- b + \sqrt{b^2 - 4ac}}{2a}$

• quando: a = 1, b = 7, c = 10

$\sf x = \dfrac{- (7) + \sqrt{(7)^2 - 4*(1)*(10)}}{2*(1)}$

$\sf x = \dfrac{- 7 + \sqrt{49 - 40}}{2}$

$\sf x = \dfrac{- 7 + \sqrt{9}}{2}$

$\sf x = \dfrac{- 7 + 3}{2}$

$\sf x = \dfrac{- 4}{2}$

$\red{\sf x = - 2}$