Question

Dada a expressão sem 45º. cos 45º + tg 30º. Calcule o seu valor.

Answer 1

tg30° = √3/3
sen45° = cos45° = √2/2

sen45° . cos45° = (√2/2)² = 2/4 = 1/2
tg30 = √3/3

$\dfrac{1}{2} + \dfrac{\sqrt{3}}{3} = \boxed{\dfrac{3+2\sqrt{3}}{6}} \\ \\ ou \\ \\ 0,5 + 1,732/3 =0,5 + 0,577 \approx \boxed{1,077}$

Answer 2

$sen45.cos45+tg30\\\frac{\sqrt{2}}{2}.\frac{\sqrt{2}}{2}+\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\\\frac{2}{4}+\frac{\sqrt{3}}{3}=\frac{6+4\sqrt{3}}{12}=\boxed{\frac{3+2\sqrt{3}}{6}}$