dada a equação x² +bx + c = 0 e sabendo que 4 e -5 são as raizes dessa equação, então temos que:
Soluções para a tarefa
Respondido por
4
Boa noite!
Solução!
![x_{1}=4\\\\\\
x_{2 }=-5\\\\\\
Fazendo~~a~~multiplicac\~ao~~das~~raizes!\\\\\\\\
(x- x_{1})\times(x-x_{2 })=0\\\\\\\
(x- 4)\times(x-(-5))=0\\\\\\\
(x- 4)\times(x+5)=0\\\\\\\
( x^{2} +5x-4x-20)=0\\\\\\\
\boxed{x^{2} +x-20=0}](https://tex.z-dn.net/?f=+x_%7B1%7D%3D4%5C%5C%5C%5C%5C%5C%0A+x_%7B2+%7D%3D-5%5C%5C%5C%5C%5C%5C%0AFazendo%7E%7Ea%7E%7Emultiplicac%5C%7Eao%7E%7Edas%7E%7Eraizes%21%5C%5C%5C%5C%5C%5C%5C%5C%0A%28x-+x_%7B1%7D%29%5Ctimes%28x-x_%7B2+%7D%29%3D0%5C%5C%5C%5C%5C%5C%5C%0A%28x-+4%29%5Ctimes%28x-%28-5%29%29%3D0%5C%5C%5C%5C%5C%5C%5C%0A%28x-+4%29%5Ctimes%28x%2B5%29%3D0%5C%5C%5C%5C%5C%5C%5C%0A%28+x%5E%7B2%7D+%2B5x-4x-20%29%3D0%5C%5C%5C%5C%5C%5C%5C%0A+%5Cboxed%7Bx%5E%7B2%7D+%2Bx-20%3D0%7D%0A%0A%0A "x_{1}=4\\\\\\
x_{2 }=-5\\\\\\
Fazendo~~a~~multiplicac\~ao~~das~~raizes!\\\\\\\\
(x- x_{1})\times(x-x_{2 })=0\\\\\\\
(x- 4)\times(x-(-5))=0\\\\\\\
(x- 4)\times(x+5)=0\\\\\\\
( x^{2} +5x-4x-20)=0\\\\\\\
\boxed{x^{2} +x-20=0}")
Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
Perguntas interessantes
Saúde,
9 meses atrás
Matemática,
9 meses atrás
Direito,
1 ano atrás
Português,
1 ano atrás
Biologia,
1 ano atrás