Question

dada a equacao do 2 grau x ao quadrado+ 8x =0 o valor de suas raizes

Answer 1

x^2+8x=0
delta=b^2-4ac
delta=8^2-4.1.0
delta=64-0
delta=64
x=-b-/+ raiz de delta/2a
x=-8-8/2.1
x=-16/2
x=-8
x=-8+8/2.1
x=0/2
x=0

Answer 2

delta = 8² - 4.1.0
delta = 64 - 0
delta = 64

-(8) +- raiz quadrada de 64 / 2.1
-8 +- 8/ 2
Raiz 1 : -8-8 / 2 = -16/2 = -8
Raiz 2 : -8+8 / 2 = 0/2 = 0