Question

da uma ajuda ai.........

Answer 1

Resposta:

Explicação passo-a-passo:

$(2x^2-2y)^7=$

$=7C_0[(2x^2)^7+(-2y)^0]+7C_1[(2x^2)^6+(-2y)^1]+7C_2[(2x^2)^5+(-2y)^2]+7C_3[(2x^2)^4+(-2y)^3]+7C_4[(2x^2)^3+(-2y)^4]+7C_5[(2x^2)^2+(-2y)^5]+7C_6[(2x^2)^1+(-2y)^6]+7C_7[(2x^2)^0+(-2y)^7]$

$=128x^{14}+7(64x^{12}-2y)+21(32x^{10}+4y^2)+35(16x^8-8y^3)+35(8x^6+16y^4)+21(4x^4-32y^5)+7(2x^2+64y^6)-128y^7$

$=128x^{14}+448x^{12}-14y+672x^{10}+84y^2+560x^8-280y^3+280x^6+560y^4+84x^4-672x^5+14x^2+448y^6-128y^7$