Question

da equação (2×-6).(3×+12)=0 e o par ​

Answer 1

(2x - 6) . (3x + 12) = 0

6x² + 24x - 18x - 72 = 0

6x² + 6x - 72 = 0

a = 6

b = 6

c = - 72

∆ = b² - 4 . a . c

∆ = 6² - 4 . 6 . (-72)

∆ = 36 + 1728

∆ = 1764

x = - b ± √∆

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2a

x' = - 6 - 42

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2 . 6

x' = - 48

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12

x' = - 4

x" = - 6 + 42

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2 . 6

x" = 36

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12

x" = 3

S = {- 4 , 3}