Question

d) y2 + 2y + 1 = 0
g) x2 - 3x - 130 = 0
j)x^2 + 12x + 32 = 0


me ajudem me enviem com cálculo por favor ​

Answer 1

Resposta:

Explicação passo-a-passo:

D)  y² + 2y + 1 = 0

 a= 1  b= 2  c= 1

-Calculo-

x=-b ±√b²-4..a.c/2.a

x=-2 ±√2²-4..1.1/2.1

x=-2 ±√4-4/2

x=-2 ±√o/2                  

x=-2 ±0/2 ------------->x= -2 +0/2  = -2/2 = -1

                                 x= -2 -0/2 = -2/2 = -1  

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G) x² - 3x - 130 = 0

  a= 1  b= -3  c= -130

-Calculo-

x=-b ±√b²-4..a.c/2.a

x=-(-3) ±√(-3)²-4..1.(-130)/2.1

x= -(-3) ±√9-(-520)/2

x= -(-3) ±√9+ 520/2

x= -(-3) ±√529/2

x= -(-3) ± 23/2 ------------->x= -(-3) + 23/2  = 3+ 23/2 = 26/2 = 13

                                        x= -(-3) - 23/2= 3 - 23/2 = -20/2 = -10

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J)x² + 12x + 32 = 0

 a= 1  b= 12  c= 32

-Calculo-

x=-b ±√b²-4..a.c/2.a

x=-12 ±√12²-4..1.32/2.1

x=-12 ±√144- 128/2

x=-12 ±√16/2

x=-12 ± 4/2 ------------->x= -12+ 4/2  = 8/2 = 4

                                    x= -12 - 4/2=  -16/2 =  -8