Question

d) y = 4x-x²
Urgenteeeeeeeeeee

Answer 1

Resposta:

$x_{1} = 0\\\\x_{2} =+4$

Explicação passo a passo:

Raízes:

4x-x²=0

Δ= b²-4.a.c

Δ=4²-4.(-1)(0)

Δ=16

$x=\frac{-b \frac{+}{-}\sqrt{Delta} }{2*a}$

$x=\frac{-4\frac{+}{-}\sqrt{16} }{2(-1)} \\\\x=\frac{-4\frac{+}{-} 4}{-2} \\\\x_{1} = \frac{-4+4}{-2} =0\\\\x_{2} =\frac{-4-4}{-2} = +4$