Question

d) x²+3×-4=0

e) ײ+6×-16=0


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Answer 1

Resposta:

d ) x² + 3x - 4 = 0

a = 1 b = 3 c = -4

∆ = 9 + 16

∆ = 25

x = -3 ± √25

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2

x' = 1

x'' = -4

e ) x² + 6x - 16 = 0

a = 1 b = 6 c = -16

∆ = 36 + 64

∆ = 100

x = -6 ± √100

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2

x' = 2

x'' = -8

Answer 2

Resposta:

Explicação passo a passo:

d

a=1

b=3

c=-4

x=-3+-V3²-4.1.-4/2.1

x=-3+-V9+16/2

x=-3+-V25/2

x=-3+-5/2

x'=-3+5/2=2/2=1

x''=-3-5/2=-8/2=-4

S={-4,1}

e

a=1

b=6

c=-16

x=-6+-V6²-4.1.-16/2.1

x=-6+-V36+64/2

x=-6+-V100/2

x=-6+-10/2

x=-6+10/2=4/2=2

x=-6-10/2=-16/2=-8

S={-8,2}