Question

D/dx de y²-(4/3)·x²·y=5

Answer 1

2ydy/dx-(8xy/3 +4/3 dy/dx) =0

2ydy/dx-4/3 dy/dx =8xy/3 ×(3)

6y dy/dx -4dy/dx =8xy

dy/dx(6y-4)= 8xy

$\frac{dy}{dx} = \frac{8xy}{6y - 4} = \frac{4xy}{3y - 2}$